Exercise 1.2 – Real Numbers

Proof-based questions with complete step-by-step explanations

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Q1 Q2 Q3

Question 1

Prove that √5 is an irrational number.

Step 1: Assume √5 is a rational number.

Then it can be written as:

√5 = a / b, where a and b are integers having no common factor and b ≠ 0.

Step 2: Squaring both sides:

5 = a² / b²

Step 3: Multiply both sides by b²:

5b² = a²

Step 4: This shows a² is divisible by 5, so a is divisible by 5.

Let a = 5k

Step 5: Substitute back:

5b² = 25k² ⇒ b² = 5k²

This implies b is also divisible by 5.

Contradiction: a and b cannot both be divisible by 5.

Therefore, √5 is irrational.

Question 2

Prove that (3 + 2√5) is irrational.

Step 1: Assume 3 + 2√5 is rational.

Then:

3 + 2√5 = a / b

Step 2: Subtract 3 from both sides:

2√5 = (a / b) − 3

The right-hand side is rational.

Step 3: Divide both sides by 2:

√5 is rational

This contradicts the fact that √5 is irrational.

Therefore, 3 + 2√5 is irrational.

Question 3

Prove that the following numbers are irrational:

(i) 1/√2    (ii) 7√5    (iii) 6 + √2

(i) 1/√2

Assume 1/√2 is rational.

Then √2 becomes rational, which is false.

Hence, 1/√2 is irrational.


(ii) 7√5

Assume 7√5 is rational.

Dividing both sides by 7 gives √5 rational.

This contradicts the fact that √5 is irrational.

Hence, 7√5 is irrational.


(iii) 6 + √2

Assume 6 + √2 is rational.

Subtract 6 from both sides:

√2 is rational — which is false.

Hence, 6 + √2 is irrational.

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