Section A (1 Mark each)

Q1. If $\alpha$ and $\beta$ are the zeroes of the polynomial $x^2 - 2x + 3k$ such that $\alpha + \beta = \alpha\beta$, then the value of $k$ is:

Q2. If one zero of the polynomial $3x^2 + 8x + k$ is the reciprocal of the other, then the value of $k$ is:

Q3. If $\alpha, \beta$ are zeroes of $x^2 + 5x + 5$, then the value of $\alpha^{-1} + \beta^{-1}$ is:

Q4. Assertion (A): The polynomial whose zeroes are 2 and -3 is $x^2 + x - 6$.
Reason (R): A quadratic polynomial with zeroes $\alpha$ and $\beta$ is given by $k[x^2 - (\alpha + \beta)x + \alpha\beta]$.

Section B (2 Marks each)

Q5. Find the zeroes of the quadratic polynomial $4\sqrt{3}x^2 + 5x - 2\sqrt{3}$ and verify the relationship between the zeroes and the coefficients.

Solve on white paper.


Q6. If $\alpha$ and $\beta$ are the zeroes of the polynomial $x^2 - x - 2$, find a quadratic polynomial whose zeroes are $2\alpha + 1$ and $2\beta + 1$.

Solve on white paper.


Q7. If the sum of the squares of the zeroes of the polynomial $x^2 - 8x + k$ is 40, find the value of $k$.

Solve on white paper.


Section C (3 Marks each)

Q8. If $\alpha$ and $\beta$ are the zeroes of the quadratic polynomial $f(x) = x^2 - 5x + k$ such that $\alpha - \beta = 1$, find the value of $k$.

Solve on white paper.


Q9. Find a quadratic polynomial whose zeroes are the reciprocals of the zeroes of the polynomial $ax^2 + bx + c, a \neq 0, c \neq 0$.

Solve on white paper.


Section D (5 Marks)

Q10. If $\alpha$ and $\beta$ are the zeroes of the quadratic polynomial $p(x) = x^2 - 3x - 2$, find a quadratic polynomial whose zeroes are $2\alpha + 3\beta$ and $3\alpha + 2\beta$.

Solve on white paper.


Section E (4 Marks)

Q11. Case Study:

A highway underpass is parabolic in shape. The curve of the underpass is represented by the polynomial $p(x) = x^2 - 2x - 8$.

(i) Find the zeroes of the polynomial $p(x)$.

(ii) Verify that the sum of zeroes is equal to $-\frac{b}{a}$.

(iii) If the graph is shifted such that the zeroes become 0 and 4, find the new polynomial.

Solve on white paper.