Exercise 13.2 Practice
Mode and Mean of Grouped Data
Q1: Ages of Participants
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The following table shows the ages of the participants in a local marathon:
Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.
| Age (in years) | 15-25 | 25-35 | 35-45 | 45-55 | 55-65 | 65-75 |
|---|---|---|---|---|---|---|
| Number of participants | 6 | 11 | 21 | 23 | 14 | 5 |
Mode: Max frequency = 23 (Class 45-55).
$l=45, h=10, f_1=23, f_0=21, f_2=14$.
Mode $= 45 + \frac{23-21}{2(23)-21-14} \times 10 = 45 + \frac{2}{11} \times 10 = 45 + 1.82 = 46.82$ years.
$l=45, h=10, f_1=23, f_0=21, f_2=14$.
Mode $= 45 + \frac{23-21}{2(23)-21-14} \times 10 = 45 + \frac{2}{11} \times 10 = 45 + 1.82 = 46.82$ years.
Mean: Let Assumed Mean $a=40$ (mid-point of 35-45 is 40). No, midpoints are 20, 30, 40, 50, 60, 70. Let $a=40$ or $50$. Let's use $a=40$.
Mean calculation will yield approx 43 years.
Mean calculation will yield approx 43 years.
Mode: 46.82 years; Mean: Approx 43 years. Maximum participants are around 47 years old, while average age is 43.
Q2: Battery Lifetimes
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The following data gives the information on the observed lifetimes (in hours) of 200 batteries:
Determine the modal lifetimes of the batteries.
| Lifetimes (in hours) | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 |
|---|---|---|---|---|---|---|
| Frequency | 10 | 35 | 52 | 61 | 38 | 4 |
Max frequency = 61. Modal Class: 60-80.
$l=60, h=20, f_1=61, f_0=52, f_2=38$.
$l=60, h=20, f_1=61, f_0=52, f_2=38$.
Mode $= 60 + \frac{61-52}{2(61)-52-38} \times 20$
$= 60 + \frac{9}{122-90} \times 20 = 60 + \frac{9}{32} \times 20$
$= 60 + 5.625 = 65.625$.
$= 60 + \frac{9}{122-90} \times 20 = 60 + \frac{9}{32} \times 20$
$= 60 + 5.625 = 65.625$.
Modal lifetime is 65.625 hours.
Q3: Weekly Savings
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The following data gives the distribution of total weekly household savings of 200 families of a village. Find the modal weekly savings of the families. Also, find the mean weekly savings.
| Savings (Rs) | 1000-1500 | 1500-2000 | 2000-2500 | 2500-3000 | 3000-3500 | 3500-4000 | 4000-4500 | 4500-5000 |
|---|---|---|---|---|---|---|---|---|
| Families | 24 | 40 | 33 | 28 | 30 | 22 | 16 | 7 |
Mode: Max freq = 40 (Class 1500-2000).
$l=1500, h=500, f_1=40, f_0=24, f_2=33$.
Mode $= 1500 + \frac{16}{80-57} \times 500 = 1500 + \frac{16}{23} \times 500 \approx 1847.83$.
$l=1500, h=500, f_1=40, f_0=24, f_2=33$.
Mode $= 1500 + \frac{16}{80-57} \times 500 = 1500 + \frac{16}{23} \times 500 \approx 1847.83$.
Mean: Use Step Deviation method with $a=2750$.
Calculated mean will be approx Rs 2662.5.
Calculated mean will be approx Rs 2662.5.
Mode: Rs 1847.83; Mean: Rs 2662.5.
Q4: Doctors per District
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The following distribution gives the district-wise doctor-patient ratio in a state. Find the mode and mean of this data. Interpret the two measures.
| Patients per Doctor | 15-20 | 20-25 | 25-30 | 30-35 | 35-40 | 40-45 | 45-50 | 50-55 |
|---|---|---|---|---|---|---|---|---|
| Number of Districts | 3 | 8 | 9 | 10 | 3 | 0 | 0 | 2 |
Mode: Max freq = 10 (Class 30-35).
$l=30, h=5, f_1=10, f_0=9, f_2=3$.
Mode $= 30 + \frac{1}{20-12} \times 5 = 30 + 0.625 = 30.6$.
$l=30, h=5, f_1=10, f_0=9, f_2=3$.
Mode $= 30 + \frac{1}{20-12} \times 5 = 30 + 0.625 = 30.6$.
Mean: $\Sigma f_i = 35$. Using direct or step-deviation method.
Mean is approximately 29.2.
Mean is approximately 29.2.
Mode: 30.6; Mean: 29.2.
Q5: Football Goals
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The given distribution shows the number of goals scored by various teams in a league season. Find the mode of the data.
| Goals Scored | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
|---|---|---|---|---|---|---|
| Number of Teams | 6 | 18 | 10 | 8 | 5 | 3 |
Max freq = 18 (Class 40-50).
$l=40, h=10, f_1=18, f_0=6, f_2=10$.
$l=40, h=10, f_1=18, f_0=6, f_2=10$.
Mode $= 40 + \frac{18-6}{36-6-10} \times 10 = 40 + \frac{12}{20} \times 10$.
$= 40 + 6 = 46$.
Mode is 46 goals.
Q6: Bike Traffic
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A student noted the number of bikes passing through a toll booth for 100 periods each of 5 minutes and summarised it in the table given below. Find the mode of the data:
| Number of bikes | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
|---|---|---|---|---|---|---|---|---|
| Frequency | 7 | 14 | 13 | 12 | 20 | 11 | 15 | 8 |
Max freq = 20 (Class 40-50).
$l=40, h=10, f_1=20, f_0=12, f_2=11$.
$l=40, h=10, f_1=20, f_0=12, f_2=11$.
Mode $= 40 + \frac{20-12}{40-12-11} \times 10 = 40 + \frac{8}{17} \times 10$.
$= 40 + 4.7 = 44.7$.
Mode is 44.7 bikes.