Mid-points $x_i$: $35, 45, 55, 65, 75, 85, 95$.
Class width $h = 10$. Choose assumed mean $A = 65$.
Step deviation $u_i = \frac{x_i - 65}{10}$: $-3, -2, -1, 0, 1, 2, 3$.
Frequencies $f_i$: $3, 7, 12, 15, 8, 3, 2$. $N = \sum f_i = 50$.
Products $f_i u_i$: $3(-3) = -9, 7(-2) = -14, 12(-1) = -12, 15(0) = 0, 8(1) = 8, 3(2) = 6, 2(3) = 6$.
$\sum f_i u_i = -35 + 20 = -15$.
Products $f_i u_i^2$: $3(9) = 27, 7(4) = 28, 12(1) = 12, 15(0) = 0, 8(1) = 8, 3(4) = 12, 2(9) = 18$.
$\sum f_i u_i^2 = 27 + 28 + 12 + 0 + 8 + 12 + 18 = 105$.
Mean $\bar{x} = A + \left(\frac{\sum f_i u_i}{N}\right)h = 65 + \left(\frac{-15}{50}\right)10 = 65 - 3 = 62$.
Variance $\sigma^2 = h^2 \left[\frac{\sum f_i u_i^2}{N} - \left(\frac{\sum f_i u_i}{N}\right)^2\right] = 100 \left[\frac{105}{50} - \left(-\frac{15}{50}\right)^2\right] = 100 [2.10 - 0.09] = 100(2.01) = 201$.
Standard deviation $\sigma = \sqrt{201} \approx 14.18$.
Mean $= 62$, Variance $= 201$, S.D. $\approx 14.18$