Decode the day for the given date

Learn the modular arithmetic method to calculate the day of the week for any given date. This topic covers century codes, month codes, and year calculations for CBSE Class 11 Applied Mathematics.

Fundamental Components of Calendar Calculations

To find the day of the week for any date, we use modular arithmetic (modulo 7). A week has 7 days, so we calculate the sum of codes for the date, month, century, and year, and find the remainder when divided by 7. The remainder corresponds to a specific day of the week, starting with Sunday=0, Monday=1, ..., Saturday=6.

Total Sum = (Date + Month Code + Year Code + Century Code + Leap Year Count) mod 7
Example 1: Find the day of the week for 15th August 1947.
Show Step-by-Step Solution

• Step 1: Identify components. Date=15. Month code for August=2.
• Step 2: Calculate Year Code. Last two digits (Y)=47. Number of leap years in 47 years = floor(47/4) = 11.
• Step 3: Century Code for 1900-1999 is 0.
• Step 4: Sum the components: (15 + 2 + 47 + 11 + 0) = 75.
• Step 5: Calculate remainder: 75 mod 7 = 5.
• Step 6: Map remainder to day: 0=Sun, 1=Mon, 2=Tue, 3=Wed, 4=Thu, 5=Fri.

Answer: Friday

Standard Reference Tables for Calculations

To perform the calculation, you must memorize or derive the reference codes: Month codes (Jan:0, Feb:3, Mar:3, Apr:6, May:1, Jun:4, Jul:6, Aug:2, Sep:5, Oct:0, Nov:3, Dec:5) and Century codes (1700-1799:4, 1800-1899:2, 1900-1999:0, 2000-2099:6). Note: For leap years, January is 6 and February is 2.

Remainder 0: Sunday, 1: Monday, 2: Tuesday, 3: Wednesday, 4: Thursday, 5: Friday, 6: Saturday
Example 1: Determine the day for 26th January 2024.
Show Step-by-Step Solution

• Step 1: Date=26. Since 2024 is a leap year, January code = 6.
• Step 2: Last two digits of year (Y) = 24. Leap years in 24 = 24/4 = 6.
• Step 3: Century code for 2000s = 6.
• Step 4: Total = (26 + 6 + 24 + 6 + 6) = 68.
• Step 5: Remainder = 68 mod 7 = 5.
• Step 6: Mapping: Remainder 5 corresponds to Friday.

Answer: Friday