A comprehensive guide on calculating the time when the hour and minute hands of a clock coincide, covering relative angular velocity and the mathematical derivation for CBSE Class 11 Applied Mathematics.
To find when the hands of a clock meet, we analyze the angular speeds of both hands. The minute hand moves 360 degrees in 60 minutes, which is 6 degrees per minute. The hour hand moves 360 degrees in 12 hours (720 minutes), which is 0.5 degrees per minute. The relative speed of the minute hand with respect to the hour hand is 6 - 0.5 = 5.5 degrees per minute (or 11/2 degrees per minute).
• At 3 o'clock, the minute hand is at 12 and the hour hand is at 3, creating a gap of 15 minutes (or 90 degrees).
• To coincide, the minute hand must cover this 90-degree gap relative to the hour hand.
• Using the formula Time = Distance / Relative Speed: Time = 90 / (11/2).
• Calculating: Time = (90 * 2) / 11 = 180 / 11 minutes.
• Converting to mixed fraction: 16 and 4/11 minutes.
Answer: The hands will coincide at 16 and 4/11 minutes past 3.
The hands of a clock coincide every (60 * 12 / 11) minutes, which is approximately 65 minutes and 5 seconds. To find the exact time for any hour 'H' between 1 and 11, we use the position of the hour hand as the starting reference point.
• Identify H = 8.
• Apply the formula: Minutes = (60/11) * 8.
• Calculate: 480 / 11 minutes.
• Perform division: 480 / 11 = 43 and 7/11 minutes.
Answer: The hands will meet at 43 and 7/11 minutes past 8.