Calculation of the time for which hands of clock meet

A comprehensive guide on calculating the time when the hour and minute hands of a clock coincide, covering relative angular velocity and the mathematical derivation for CBSE Class 11 Applied Mathematics.

Relative Angular Velocity of Clock Hands

To find when the hands of a clock meet, we analyze the angular speeds of both hands. The minute hand moves 360 degrees in 60 minutes, which is 6 degrees per minute. The hour hand moves 360 degrees in 12 hours (720 minutes), which is 0.5 degrees per minute. The relative speed of the minute hand with respect to the hour hand is 6 - 0.5 = 5.5 degrees per minute (or 11/2 degrees per minute).

Relative Speed = 5.5 degrees/min = 11/2 degrees/min
Example 1: At what time between 3 o'clock and 4 o'clock do the hands of a clock coincide?
Show Step-by-Step Solution

• At 3 o'clock, the minute hand is at 12 and the hour hand is at 3, creating a gap of 15 minutes (or 90 degrees).
• To coincide, the minute hand must cover this 90-degree gap relative to the hour hand.
• Using the formula Time = Distance / Relative Speed: Time = 90 / (11/2).
• Calculating: Time = (90 * 2) / 11 = 180 / 11 minutes.
• Converting to mixed fraction: 16 and 4/11 minutes.

Answer: The hands will coincide at 16 and 4/11 minutes past 3.

General Formula for Coincidence

The hands of a clock coincide every (60 * 12 / 11) minutes, which is approximately 65 minutes and 5 seconds. To find the exact time for any hour 'H' between 1 and 11, we use the position of the hour hand as the starting reference point.

Minutes past H = (60/11) * H
Example 1: Find the time between 8 and 9 o'clock when the hands meet.
Show Step-by-Step Solution

• Identify H = 8.
• Apply the formula: Minutes = (60/11) * 8.
• Calculate: 480 / 11 minutes.
• Perform division: 480 / 11 = 43 and 7/11 minutes.

Answer: The hands will meet at 43 and 7/11 minutes past 8.