Chapter 4: Quadratic Equations
Overview
This page provides comprehensive Chapter 4: Quadratic Equations – Board Exam Notes aligned with the latest CBSE 2025–26 syllabus. Covers standard form, factorisation, quadratic formula (Sridharacharya), discriminant & nature of roots, and situational word problems.
Factorisation • Quadratic Formula • Discriminant • Nature of Roots • Word Problems
Exam Weightage & Blueprint
Total: 4-6 MarksThis chapter falls under Unit II: Algebra (20 marks total). As per the latest syllabus: solve quadratic equations by factorisation and quadratic formula, determine nature of roots using discriminant, and solve real-life situational problems.
| Question Type | Marks | Frequency | Focus Topic |
|---|---|---|---|
| MCQ | 1 | High | Nature of Roots (Discriminant) |
| Short Answer | 2 or 3 | Medium | Solving by Factorisation/Formula |
| Long Answer | 4 or 5 | Medium | Word Problems (Speed/Age/Area) |
⏰ Last 24-Hour Checklist
- Standard Form: $ax^2 + bx + c = 0, a \neq 0$.
- Discriminant: $D = b^2 - 4ac$.
- Quadratic Formula: $x = \frac{-b \pm \sqrt{D}}{2a}$.
- Nature of Roots: $D > 0, D = 0, D < 0$.
- Speed Formula: Time = Distance / Speed.
- Dimension Check: Length cannot be negative.
📐 Concepts & Solving Methods
1. Method of Factorisation
Split the middle term $bx$ such that the product of the two parts equals $ac$.
Split $-5x$ into $-2x$ and $-3x$ because $(-2)(-3) = 6 = (2)(3)$.
2. Quadratic Formula (Sridharacharya Formula)
The roots of $ax^2 + bx + c = 0$ are given by:
🧮 Nature of Roots (Discriminant)
The Discriminant is $D = b^2 - 4ac$. It determines the nature of roots without solving.
| Value of D ($b^2 - 4ac$) | Nature of Roots | Roots |
|---|---|---|
| D > 0 | Two Distinct Real Roots | $\frac{-b \pm \sqrt{D}}{2a}$ |
| D = 0 | Two Equal Real Roots | $-\frac{b}{2a}, -\frac{b}{2a}$ |
| D < 0 | No Real Roots | Imaginary |
Quadratic Root Finder
Enter coefficients for $ax^2 + bx + c = 0$
Solved Examples (Board Marking Scheme)
Q1. Find the discriminant of $2x^2 - 4x + 3 = 0$ and find the nature of roots. (2 Marks)
Q2. The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides. (4 Marks)
Previous Year Questions (PYQs)
Ans: For equal roots, $D = 0 \Rightarrow b^2 - 4ac = 0$.
$k^2 - 4(2)(3) = 0 \Rightarrow k^2 = 24 \Rightarrow k = \pm 2\sqrt{6}$.
Ans: Split $7x$ into $2x + 5x$. Roots are $-\sqrt{2}, -\frac{5}{\sqrt{2}}$.
Ans: Eq: $\frac{360}{x} - \frac{360}{x+5} = 1$. Solving gives $x = 40$ km/h ($x=-45$ rejected).
Exam Strategy & Mistake Bank
⚠️ Mistake Bank
💡 Scoring Tips
Concept Mastery Quiz 🎯
Test your readiness for the board exam.
1. The quadratic equation $ax^2 + bx + c = 0$ has no real roots if:
2. The roots of the equation $x^2 - 3x - 10 = 0$ are:
3. Which of the following is NOT a quadratic equation?
4. For a quadratic equation to have equal roots, the discriminant must be:
5. The sum of roots of ^2 - 5x + 2 = 0$ is:
📝 More Solved Board Questions
Sol. We need two numbers whose product = $6 \times (-2) = -12$ and sum = $-1$.
Those numbers are $-4$ and $3$: $(-4)(3) = -12$, $-4 + 3 = -1$
$6x^2 - 4x + 3x - 2 = 2x(3x-2) + 1(3x-2) = (2x+1)(3x-2) = 0$
$x = -\frac{1}{2}$ or $x = \frac{2}{3}$
Sol. For equal roots: $D = 0$
$D = (2)^2 - 4(k)(1) = 4 - 4k = 0$
$4k = 4 \Rightarrow$ $k = 1$
Sol. Let speed = $x$ km/h. Time = $\frac{480}{x}$ hours.
At new speed: $\frac{480}{x+8} = \frac{480}{x} - 2$
$480x - 480(x+8) = -2x(x+8)$
$-3840 = -2x^2 - 16x$
$x^2 + 8x - 1920 = 0$
Using formula: $x = \frac{-8 \pm \sqrt{64 + 7680}}{2} = \frac{-8 \pm 88}{2}$
$x = 40$ (taking positive value; $x = -48$ rejected as speed > 0)
Speed = 40 km/h
📋 Board Revision Checklist
- ✅ Standard form: $ax^2 + bx + c = 0$, $a \neq 0$
- ✅ Factorisation: find two numbers with product $= ac$ and sum $= b$
- ✅ Quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
- ✅ Discriminant: $D = b^2 - 4ac$
- ✅ $D > 0$ → Two distinct real roots
- ✅ $D = 0$ → Two equal real roots $\left(x = -\frac{b}{2a}\right)$
- ✅ $D < 0$ → No real roots
- ✅ For real roots: use condition $D \geq 0$ (not just $D > 0$)
- ✅ Always reject negative values for length/speed/age with justification
“Equal roots” → $D = 0$. “Real roots” → $D \geq 0$. “No real roots” → $D < 0$. Getting this distinction right is guaranteed 1 mark in MCQ/SA questions.